3) One card is drawn from a well-shuffled deck of 52 cards. What is the probability of getting a black face card?
a) 1/26
b) 3/14
c) 2/26
d) 3/13

4) If x = a[(sec theta + tan theta)^2] and y = b[(sec theta – tan theta)^2], then ,
Prove that (xy)^2 = (ab)^2.

Question

3)	One card is drawn from a well-shuffled deck of 52 cards. What is the probability of getting a black face card?
a)	1/26
b)	3/14
c)	2/26
d)	3/13

4)	If x = a[(sec theta + tan theta)^2] and y = b[(sec theta – tan theta)^2], then ,
Prove that (xy)^2 = (ab)^2.

anonymous · Answer

there are 26 black cards in the deck so that is 26/52 and there are 12 face cards so that is 12/52 multiply and you get 3/26 but thats not on there

anonymous · Answer

yeah, for that, I was confused. Anyway Thankss a lot.

anonymous · Answer

such simple questions

anonymous · Answer

No bhai, I was worried. Becoz in the answer key, "b" is given as correct answer. So was confused.