Question

Really need help with this problem in attachment!

Answer 1

here it is

Answer 2

hmmm.....i think it should be a quad equation............

Answer 3

The equation I thought it would be is this x = 1/16 (x - 3)^2

Answer 4

x=1/3(y-3)

Answer 5

err
x=1/3(y-3)^2

Answer 6

*x = 1/16 (y - 3)^2

Answer 7

x= 1/9(y-3)^2

Answer 8

when y = 0 x =1
when y = 3 x = 0

Answer 9

Wait
x = -1/16 (y - 3)^2
There we go, how would 1/9 find the focus or directrix?

Answer 10

if u switch variables then u rotate the graph 90 degrees

Answer 11

plot: y= 1/9(x-3)^2

Answer 12

should be -1/9 accutally

Answer 13

ok, I just did and it doesn't look like the graph about

Answer 14

I just graphed my equation, and it was right. Thank you so much for helping :)

Answer 15

ur equation is wrong.

Answer 16

I graphed mine on a graphing calculator and it comes up as the exact graph above.

Answer 17

never mind

Answer 18

graph was too small to see that it took 4 units instead of 3 to equal 1

Answer 19

It's cool, well thank you for the help

Answer 20

post a bigger graph next time my eyes are funny =D

Answer 21

haha I will try :)