suppose you need to solve a system of 2 equations in which one equation is y=(x+2)(x-3)(x-6) and the other equation represents a horizontal line. how many soluions could your system have?

how do i do this?

Question

suppose you need to solve a system of 2 equations in which one equation is y=(x+2)(x-3)(x-6) and the other equation represents a horizontal line. how many soluions could your system have?

how do i do this?

mertsj · Answer

Sketch the graph.  The function has zeros at -2, 3 and 6.  If x is a number far to the left (maybe -100), the the y value would be a "big": negative number.  If x is far to the right, y would be a big positive number.  So let's put all of that on the graph.

mertsj · Answer

|dw:1323376266343:dw|