what would be the horizontal asymtote of (x-1)(x-2)(x-3) / (4x+1)?
i kind of already know what he's saying....
i wanna know why this HA isnt 1/4
o cause the degree is larger?
what is the y-intercept of this?
the answer was: NONE
what is the y intercept
Vertical asymptote is -1/4 but horizontal is 0
y intercept is not 0,-6
Plug in x to be 0 and you get your y-int
ok my hw site counted my answer wrong because i put 0,-6... it accepted it when i put just -6 though
i wasnt arguing -_-
what would the graph of 3/(x+1)^2(x-3) look like? my calc is giving me the wrong answer
Type it like this in your calc.. (3)/((x+1)^2(x-3)) and it should look like this http://www.wolframalpha.com/input/?i=%283%29%2F%28%28x%2B1%29^2%28x-3%29%29&t=mfftb01
mine still doesnt look like the right answer
Maybe your zoomed in or out too far..Or your window isnt set properly.
I got it to work on mine.
i have the max's and min's set to 10 and -10
Set them to -6.5 and 6.5
it still doesnt quite look like the right answer
|dw:1323471528673:dw|
thats what i get
are you typing it in like i showed above?
With all the parenthesis
o i forgot to put in some of the parenthesis
i feel slow...
Gotta put em all in there or it wont work lol
well thanks. im done for now. need sleep.
|dw:1323471697275:dw|
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