Question

Two fair dice are thrown simultaneously. The random variable H is the highest common factor of the two scores. Tabulate the probability ditribution of H, combining together all the possible ways of obtaining the same value.

Answer 1

The answers are
1= 23/36
2=7/36
3=3/36
4=1/36
5=1/36
6=1/36

and it's probability distributions...

Answer 2

I'm not sure how they got those answers.

Answer 3

yeah the problem is weird

Answer 4

i thought they meant the highest of the 2 dice

Answer 5

they want the GCF of the two dice

Answer 6

Yes, they do. I'm not sure how to approach the question with the GCF

Answer 7

in order for the gcf to be 6, both dice have to be 6 -> 1/6 * 1/6 = 1/36

Answer 8

similar for 4 and 5

Answer 9

for the gcf to be 3, both dice must be 3 or 6, but not both 6 because then the gcf would eb 6

Answer 10

2/6*2/6 - 1/36 = 3/36

Answer 11

for the gcf to be 2, both dice must be 2,4 or 6, but not both 4 and not both 6

Answer 12

= 3/6*3/6 - 1/36 - 1/36 = 7/36

Answer 13

and the rest would have GCF of 1

Answer 14

Ok, it makes more sense now. Thanks :)