Question

Decompose into Partial Fractions

(6x-26)/(x-3)(x-3)

Answer 1

A B
---- +-------
(x-3) (x-3)^2

Answer 2

but why (x-3)^2?

Answer 3

when it is square we have to write is like this

Answer 4

if it were (6x-26)/(x-3)(x-3)(x-3)

A B C
---- +------- + --------------
(x-3) (x-3)^2 (x-3)^3

Answer 5

thx a lot dude

Answer 6

that really helped me

Answer 7

Here is a great lesson on partial fractions (pauls online math notes) http://tutorial.math.lamar.edu/Classes/CalcII/PartialFractions.aspx

The rest of his website is pretty amazing. :)

Answer 8

(6x-26)/(x-3)(x-3) = A / (x-3)^2 + B / (x-3)

now multiply thru by (x-3)^2
to get an identity in x,A and b