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What is the distance from M(-1, 6) to N(11, 1)? A) 12 units C) 13 units B) 149−−−√ units D) 169 units
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\[Distance=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\] where \[(x_1,y_1)=(-1,6) ;(x_2,y_2)=(11,1)\]
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B)\[\sqrt{149}\]
\[\sqrt{(-1-11)^2+(6-1)^2}=\sqrt{(-12)^2+5^2}=\sqrt{144+25}=\sqrt{169}=13\]
It's C. -1 - 11 = -12, -12^2=144 6-1=5, 5^2=25 144+25 is 169 and the square root of 169 is 13.
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jimmy, are you a teacher?
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