The length of a rectangle is 3m more than twice its width, and the area of the rectangle is 77m^2 . Find the dimensions of the rectangle.
that would be the formula to find the length and width?
Well, it gave the area, so we have to use the formula for area of a rectangle to find it A = xy
2x + 3 = length x = width A = x(2x+3) 77 = 2x^2 + 3x 2x^2+3x - 77 = 0 Now it's correct :D
so to get the length and width have to solve the equation right?
Yes 2x^2+3x - 77 = 0 2x^2 + 14x - 11x - 77 = 0 2x(x+7)-11(x+7) = 0 (x+7)(2x-11) = 0 x = -7 x = 11/2 or 5.5 2x + 3 = 14
5.5 x 14 = 77
By the way x = -7 is not a solution
so then if the width is -7 ..?
and the length is 14
No. If you notice, there are two solutions for x. I already told you that x = -7 is not a solution.
then the length is 14 "?
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