what is the equation of the line in slope-intercept form that passes the point (1,3) and is perpendicular to the line y=-x+2?

a.y=x-4
b. y=x+2
c.y=-x+2
d. y=-x-4

Question

what is the equation of the line in slope-intercept form that passes the point (1,3) and is perpendicular to the line y=-x+2?

a.y=x-4
b. y=x+2
c.y=-x+2
d. y=-x-4

anonymous · Answer

the slope of the line is -1
plug m = -1 and x1=1, y1= 3 into the standard equation
y-y1 = m(x-x1)
simplify and rearrange to  the required form

hoblos · Answer

the slope of the line is 1

anonymous · Answer

is it a b c or d ?

hoblos · Answer

b

anonymous · Answer

sorry slope is 1 - i misread the question

anonymous · Answer

can someone show me step by step how to do this i dont know how to do this

hoblos · Answer

since the line is perp. to y=-x+2 => slope * -1 must be = -1
=> slope = 1
applying the formula: y-y1 = m(x-x1)
you get y-3=1(x-1)
       =>   y=x+2

anonymous · Answer

what the formula is called ?