A woman is 66 7/12" tall and her son is 58 7/9" tall. How many inches taller is the woman?
\[ 66\frac{7}{12} -58\frac{7}{9} \] \[\frac{799}{12}-\frac{529}{9} \]
Then you can get the numerator to be the same, and find the difference of the fraction to get the difference of heights.
My calculator died on me, so you'll have to figure that bit out on your own.
not sure of next step?
Ok, well, this'll take some time, but I'll show you.
I thought answer was 12".
\[\frac{799\times12}{108}- \frac{529\times12 }{108} \]
sorry, 799times9
how do you get the 108?
ok. 9 x12?
you do 799 times 9 and 529 times 12, so that the bottom can equal 108
\[ \frac{7191-6348}{108} \]
\[ \frac{843}{108}inches\] should be the answer which you can simplify
Am so lost!
Where did you get lost?
how did you get to the difference in inches when the fractions are so uneven?
I made the fractions even by making them first into Whole fractions, and then making the denominators the same so that I could take away both fractions. Then I got a large Whole fraction, which I placed again into a simplified verion, which is actually 7"87/108 now that I see it.
so 66 7/12 = p (mother) 58 7/9= h (son) and subtract h from p to get ?
to get the difference in height of the two, which results in how much taller the woman is than the son.
p= 799*9=7191/108 and h= 529*12=6348/108 reduce to 843/108?
Yup, which is the answer. You can get that as a proper fraction by dividing 843 by 108 and finding the remainder, then placing the remainder over 108, which gives 7 87/108"
so the mother is 7" taller?
yup, 7 and 87/108" taller
or does it have to be 7 87/108" taller?
Yes, it has to be the second as it's 7.80 inches if you use it as a decimal point.
7 87/108" taller
how do i simplify 7 87/108?
7 29/36
that's the most simplified verion.
so the lowest divisible is 3 right?
Yup :)
THANK YOU!
you're welcome :) You understand it now?
yes thanks.
great :)
Join our real-time social learning platform and learn together with your friends!