Question

please helppp

Answer 1

Not sure if we can help very much without knowing the definition of f and g.

Answer 2

f(X) = tan pix/2 and g (x)= 1/2 sex pix/2 , Sorry!

Answer 3

If f(x)=tan(pi x/2) and
g(x)=(1/2)sec(pi x/2) (I assume there is a typo, haven't heard of that in maths)
Assume x not equal to 1 (where f(x) and g(x) are not defined), we can multiply each by cos(x) to get
2f<2g
or
sin(pi x/2) < (1/2)

Usng sin(pi/6)=1/2 and sin(-7pi/6)=1/2, the interval should be [-7pi/6, pi/6], or for x, [-7/3, 1/3].

But there is no such choice from your list.
So please check for typos in the question, or check for my mistakes.

If you can't find anything, it would probably be choice 1 "none of these".

Answer 4

it was none of the answers :) so for the same functions that has the interval (-1,1) how would i approximate the interval where f<g

Answer 5

for x in (-1,1)
You have f<g for x in [-1,1/3), since the part (-7/3,-1) is not on the interval.

Answer 6

thank you so much

Answer 7

You're welcome!