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the difference between six times a number and 9 is equal to five times the sum of the number and 2. Find the number.
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"six times a number" = 6x "the difference between six times a number and 9" = 6x-9 "sum of the number and 2" = x + 2 "five times the sum of the number and 2" = 5(x+2).
6x-9=5(x+2)
Bingo! Solve for x.
how do i solve that?
x=19!
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can you show me how you did that plz?
It's basic algebra from there. First step is to use the distributive property: \[a(b+c)=ab+ac\]\[\Rightarrow 5(x+2)=5x+5(2)\]
So \[6x-9=5x+10\]Take 5x from both sides:\[6x-5x-9=5x-5x+10\]\[\Leftrightarrow x-9=10\]Add 9 to both sides:\[x-9+9 = 10+9\]\[\Leftrightarrow x=19\]
right what Dalvoron said ^.
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