Question

Combination factoring
Common factor and difference of squares of following equation

2x^2-32

Answer 1

first rewrite as
\[2(x^2-16)\] and then factor as the difference of two squares

Answer 2

how would you write that as the difference of two squares

Answer 3

\[x^2\] is the square of
\[x\] and
\[16\] is the square of
\[4\] so it is like having
\[a^2-b^2\] with
\[a=x,b=4\]

Answer 4

so if for example the equation was 18x^2-32y^2.... how would you figure this out

Answer 5

you would first change it to 2(9x^2 - 16y^2) ... then what

Answer 6

you would recognize
\[9x^2=(3x)^2, 16y^2=(4y)^2\] and then write
\[(3x)^2-(4y)^2=(3x+4y)(3x-4y)\]