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Mathematics 22 Online
OpenStudy (anonymous):

find the mean of 2,4,3,4,6,1,4,7,2,9,2,6,3,3,3,6,2,7 and 3.2 identify the outlier then find the mean without the outlier

OpenStudy (anonymous):

mean is average, u know how to find the average?

OpenStudy (anonymous):

add all /?

OpenStudy (anonymous):

http://www.ehow.com/how_5201412_calculate-outliers.html yes

OpenStudy (anonymous):

and outlier? without outlier?

OpenStudy (anonymous):

mean is 4.1 to find the outlier, use the link and then find the mean again

OpenStudy (matt101):

An outlier is a number that is either much higher or much lower than most of the other numbers. In this case, I would probably say 9 is the outlier since the data seems to be more concentrated around the lower numbers. Therefore just recalculate the average but don't use 9.

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