Question

solving for y help

Answer 1

\[\tan (\sqrt{y})=x/2+C_{2}\]

Answer 2

\[\sqrt{y}=\tan^{-1}(\frac{x}{2}+C_2)\] i guess is a start. maybe i don't understand the question

Answer 3

can i always divide by tan or is it only under special circumstances?

this is what the original problem was

\[y'=\sqrt{y}\cos (\sqrt{y})\]

and this is what my answer is

\[y=\tan^{-1} (x/2 +C _{2})^2\]