Question

write an equation for the line that is perpendicular to the given line and that passes through the given point. y=6x-2;(0.0)

Answer 1

The slope of the line y = 6x - 2 is 6. A line that is perpendicular to it would have a slope that is the negative reciprocal, which is -1/6.

The equation for the perpendicular line can be expressed as y = mx +b. We have the slope, m, and the question gives a point, so we have x and y. Therefore plug in the values and solve for b:

0 = (-1/6)(0) + b
b = 0

The general equation for the line is therefore y = (-1/6)x