Question

find the middle term in the expression of (3x-x^3/6)^8

Answer 1

Using pascal triangle, the 8th (technically 9th, but the one we use for the 8th power) row is:

1 8 28 56 70 56 28 8 1

Middle Term coefficient is:

70

So middle term is:

\[70 * (3x)^4 * (-x^3)^4\]

Answer 2

There's a divisor of 6 in the second term:
\[70*(3x)^{4}*(-x ^{3}/6)^{4}\]

Answer 3

Sorry, didn't the the /6 there.

\[70 * (3x)^4 * (-{{x^3}\over 6})^4\]