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Could someone explain to me how 3^2 ≡ 2 (mod 7)?
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1 2 3 4 5 6 7 8 9 ^
Whats confusing me is I thought 3^2 and 2 had to have the same remainder when divided by 7.
9/7 = 1R2 2/7 = 0R2
that works as well
oh!
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i get it. thx!
mod is just the remainder after division. 9 divided by 7 gives a remainder of 2.
ok, one last thing. I'm looking at this congruence that says 6≡ -1 (mod 7). Is that because 6/7 = 1 ?
7/6= 1 , sry
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