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Mathematics 21 Online
OpenStudy (anonymous):

In the figure below, CE and AB are parallel and CE is the bisector of angle ACD. If angle ACD measures 110 degrees, what is the measure of arc BC?

OpenStudy (anonymous):

OpenStudy (anonymous):

(you don't have to give me a straight answer. I would rather be walked through it because I need help on it.)

OpenStudy (anonymous):

55 degrees.

OpenStudy (amistre64):

arcBC should be 2 times the measure of angleA i think

OpenStudy (anonymous):

Angles ACE and ECD are same (bisector). The total is 110. So, each is 55 degrees.

OpenStudy (anonymous):

Because AB and CE are parallel, angle BAC must equal angle ACE = 55 degrees.

OpenStudy (anonymous):

but the arc of BC is what I'm trying to find, how would I know the measure of that arc?

OpenStudy (amistre64):

OpenStudy (anonymous):

(this is where I always get confused)

OpenStudy (amistre64):

there is a thrm which pretty much goes like this:

OpenStudy (amistre64):

|dw:1323795621919:dw|

OpenStudy (amistre64):

the arcLength is either the central angle; or twice the angle thats on the rim of the circle

OpenStudy (amistre64):

since in your picture: A is the angle measureing arcBC, we need to determine A and double it

OpenStudy (anonymous):

oh wait....

OpenStudy (anonymous):

the other guy said A would equal 55 since AB is parallel to CE

OpenStudy (amistre64):

right, A = 55

OpenStudy (anonymous):

so 110

OpenStudy (anonymous):

is A doubled

OpenStudy (amistre64):

correct, arcBC = 110

OpenStudy (anonymous):

Oh, thank you !!

OpenStudy (amistre64):

yep

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