can someone tell me where do you plug in the numbers...
where do you plug in the 5/2 and the -1
at first you put t=5/2 in the whole equation, evaluate it and then evaluate it for t=-1 subtravt the latter from the former
example [t^2] upper limit is 6, lower limit is 3 so 6^2-3^2
k thanks :)
why does it not come out..?
what denebel?
maybe the equation is too long and I am making a computational mistake?
In the example, I plug in 5/2 to all the t's and subtract it by the value if all the t's were -1, right?
\[2/7(1/3t^2-5/2t^2+6/\pi \sin(\pi*t))\] t=5/2 a=2/7(25/12-125/8+6/pi*1) t=-1 b=2/7(1/3-5/2+0) a-b=2/7(25/12-125/8+6/pi-(1/3-5/2)) a-b=2/7(25/12-125/8+6/pi-1/3+5/2)
a-b or b-a?
typo?
a-b, first upper limit then lower
oh, isn't upper limit represented by b?
no upper is by a where t=5/2 lower by b t=-1
ok, thank you.
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