Question

can someone tell me where do you plug in the numbers...

Answer 1

where do you plug in the 5/2 and the -1

Answer 2

at first you put t=5/2 in the whole equation, evaluate it and then evaluate it for t=-1
subtravt the latter from the former

Answer 3

example [t^2] upper limit is 6, lower limit is 3
so 6^2-3^2

Answer 4

k thanks :)

Answer 5

why does it not come out..?

Answer 6

what denebel?

Answer 7

maybe the equation is too long and I am making a computational mistake?

Answer 8

In the example, I plug in 5/2 to all the t's and subtract it by the value if all the t's were -1, right?

Answer 9

\[2/7(1/3t^2-5/2t^2+6/\pi \sin(\pi*t))\]
t=5/2
a=2/7(25/12-125/8+6/pi*1)
t=-1
b=2/7(1/3-5/2+0)
a-b=2/7(25/12-125/8+6/pi-(1/3-5/2))
a-b=2/7(25/12-125/8+6/pi-1/3+5/2)

Answer 10

a-b or b-a?

Answer 11

typo?

Answer 12

a-b, first upper limit then lower

Answer 13

oh, isn't upper limit represented by b?

Answer 14

no upper is by a where t=5/2
lower by b t=-1

Answer 15

ok, thank you.