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How do you solve for b in y=mx+b
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y-mx=b
b = y - mx
they are wrong, the answer is\[b=({1\over({1\over y-mx})^{2+e^{\pi i}}})^{0.999...}\]
seriously, above is true but more importantly the answer, I think, to the question "How do you solve for b" is "subtract mx from both sides"
Turing Test, try not to be a smart aleck
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Sorry, I'm just a bit tired of giving away answers. I want the student to think a little, even if it makes me look like a jerk. My point was that we should have replied to this question with "subtract mx from both sides" in order to make the student do some work, in the hope that they may actually learn something here. High aspirations I know.
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