Solve y=2x-1 2x-y-1=0
Replace (2x-1) in the place of y in second equation.
they ask if the system has exactly one solution or if it has infinitely many solutions. which would be my answer for this equation?
Infinitely many solutions
show the steps please
y=2x-1 2x-y-1=0 2x-(2x-1)-1=0 2x-2x+1-1=0 2x-2x=0 So infinitely many solutions
2x-2x=0 2x=2x
why does the 2x=2x if right before that it was 2x-2x=0? wouldn't it be 0=0?
2x-2x=0 0=0 If we add both sides by 2x then.. 2x-2x+2x=0+2x 2x=2x
why did you need to add the] 2x?
It's not needed, 2x-2x=0 is enough
If it wasn't needed, why'd you add 2x to -2x and to the 0 ?
If we add 2x also it doesn't matter. It was just another way of showing that they can have infinite values.
How did you know that it was gonna be infinite value?
2x=2x give any value to x, it's same.
in the beginning why did we have to Replace (2x-1) in the place of y in second equation. ?
i need step by step instructions.
If there are two variables with one equation it's not possible to get the answer. But in this question there are two equation's only using the variables x and y. So first try to write x in terms of y or y in terms of x. For Eg. 4x-y=4 You cannot solve the above equation without knowing x or y value or x in terms of y or vice versa. For above equation if it's given that y=2x then replace 2x in place of y so there is only on variable, and you can solve. 4x-2x=4 2x=4 x=2 y=2x=4 Understood?
Ohkay I get it with that example. show me another?
You try to make a question and solve..
Why me? I'm the one that's lost/:
It would improve your ability to make question's. You try to make a question similar to the one you posted.
3x+y=4 -3x=y-7
what would be step by step for this one?
You try to do, I will say, if you made any mistake.
First try to make x in terms of y or vice versa
how do i do that?
3x+y=4 y=4-3x Substitute this value in second equation
I'm so dumb -_- I don't get what you did to the second equation. I mean like i just dont know how you do that to ever probelm..
yvette, what you need to do is notice that the second equation is all setup with a y=... so you can use what y equals to substitute into the first equation. fror example with the one you just posted: 3x+y=4 y=4-3x you can substitute (4-3x) for the y in the first equation... so... 3x + (4-3x) = 4 then continue to solve... 3x + 4 - 3x = 4 then you should notice that both sides can be made to be the same: 3x + 4 = 3x + 4
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