Question

How do I factor the sum or difference of two cubes?

Answer 1

a^3 + b^3 = (a + b) (a^2 - ab + b^2)

a^3 - b^3 = (a-b) (a^2 +ab +b^2)

Answer 2

Example problem is \[v ^{7} + 27\]

Answer 3

v^7 ?

Answer 4

yep

Answer 5

27 = 3^3

Answer 6

Sorry forgot the v at the end of 27

it should be v^7 + 27v

Answer 7

o ok

v (v^6 + 27)

v (v^2 + 3) (v^4 - 3v^2 + 9)

Answer 8

Hmm. I got up to \[v[(v^2)^3 + (3)^3]\]

Answer 9

yes

Answer 10

then I got v[(v^2 + 3) but got lost at the v^4 in the trinomial

Answer 11

For this case,
let v^2 be a
and let 3 be b

plug the values of a and b in
(a + b) (a^2 - ab + b^2)

Answer 12

Oh I get it the (v^2)^2 equals v^4 thks for the help