sketch graph of parabola..find the vertex..
y=-x2^2+2x-7....

Question

sketch graph of parabola..find the vertex.. 
y=-x2^2+2x-7....

gsx · Answer

What do you mean with x2^2?

anonymous · Answer

-2x + 2 = 0
x = 1

vertex is (1, -6)

anonymous · Answer

its -x^2+2x-7

gsx · Answer

With a formula like ax^2+bx+c, you can find the x coordinate of the vertex with:
-b/2a. In this case -2/-2=1. Then you calculate y(x).

turingtest · Answer

@BLVSL do you know about wolfram alpha? http://www.wolframalpha.com if you just want graphs and answers, this is the site for you. If you want detailed tutoring, open study is better

anonymous · Answer

@moneybird.. i put down the wrong problem can u double check..

turingtest · Answer

here's your problem: http://www.wolframalpha.com/input/?i=y%3D-x2%5E2%2B2x-7

anonymous · Answer

turingtest thanks will check..

anonymous · Answer

-x^2+2x-7 ?
then it's correct

gsx · Answer

Ehm it is http://www.wolframalpha.com/input/?i=y%3D-x%5E2%2B2x-7

anonymous · Answer

correct

turingtest · Answer

oh, I see you corrected your formula, here is the corrected form in wolfram: http://www.wolframalpha.com/input/?i=y%3D-x%5E2%2B2x-7

turingtest · Answer

click "properties" to find the vertex, line of symmetry, etc.