Question

Use the function value and constraint to evaluate the given trigonometric function:
-Function value: sec theta= -4
-constraint: tan theta < 0
-evaluate: cot theta
please show work.

Answer 1

Okay you would need \( \tan^2 \theta +1 = \sec ^2 \theta \)

Answer 2

and \( \tan \theta = \frac 1 {\cot \theta} \) can you do the rest ?

Answer 3

I'm confused about the tan squared and sec squared

Answer 4

It's an identity, try to prove it using right-angle triangle, it's actually very easy.

Answer 5

but idk what x or y is to get the legs of the right angle triangle

Answer 6

sec theta = -4 ( r/x) so can sec be -59/14.8?