8. Consider the linear system
x + 2y = -1
3x+ay=-3
1.-For which values of "a" does this system have no solutions?
2.-For which values of a does this system have one solution?
3.-Infinitely many solutions?

Question

8. Consider the linear system 
x + 2y = -1
3x+ay=-3
1.-For which values of "a" does this system have no solutions? 
2.-For which values of a does this system have one solution? 
3.-Infinitely many solutions?

anonymous · Answer

Do you have any ideas how to solve it?

anonymous · Answer

I graphed the first one and i am working from there

anonymous · Answer

You could try to solve the system. For example, multiply the first equation by (-3) and then add the two equations

anonymous · Answer

$$(a-6)y = 0$$

anonymous · Answer

If a = 6, then any value of y is a solution of the system.

anonymous · Answer

If a = 0 the only solution is y = 0

anonymous · Answer

give me a moment while I take a look at your question?

anonymous · Answer

did you solve it?

anonymous · Answer

yes, thanks :)

anonymous · Answer

for which values of "a" the system have no solutions?