Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (pokemon23):
what kind of math...?
OpenStudy (anonymous):
OpenStudy (anonymous):
???
OpenStudy (mr.math):
Which problem do you need help with?
OpenStudy (anonymous):
all?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Do you have any idea how to get started?
OpenStudy (mr.math):
I will help you with two problems, you'll need to try the other.
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
btw show work?
OpenStudy (pokemon23):
Exchange medal time :)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (mr.math):
Lets start with the first one. We have two objects, one weighs 3 and the other weighs w. We need the sum of their weights to be 7. In mathematical notation \(3+w=7\). By subtracting \(3\) from both sides, we get \(w=7-3=4\).
OpenStudy (akshay_budhkar):
omg! blunder!
OpenStudy (mr.math):
For the second problem, there are 5 objects each weighs n and they add up to 25 mass unit. That's \(5n=25 \implies n=\frac{25}{5}\iff n=5\).
OpenStudy (mr.math):
Tell me how much does x weigh in problem 3.
OpenStudy (anonymous):
3? but i need help with showing work??
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (mr.math):
Correct! You have \[x+x+7=`3\]
OpenStudy (mr.math):
x plus x is 2x. So
\[2x+7=13\]
OpenStudy (mr.math):
Now, you need to isolate x from any number. So subtract 7 from both sides,
\(2x+7-7=13-7\), which is the same as
\[2x=6\]
OpenStudy (mr.math):
Now, you want to get rid of x's coefficient. Divide both sides by 2:
\[x=3.\]
OpenStudy (mr.math):
Easy?!
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
was that all for number 3?
OpenStudy (mr.math):
Hmm, yeah.
OpenStudy (anonymous):
can you help me on all of them il give u good answer?
OpenStudy (mr.math):
I would love to help you without even giving me good answer, but you won't learn anything this way. I want you to try, so you can learn from your mistakes.
OpenStudy (anonymous):
please only this assignment iv been trying all day
Still Need Help?
Join the QuestionCove community and study together with friends!