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Mathematics 24 Online
OpenStudy (anonymous):

I need some math help?

OpenStudy (pokemon23):

what kind of math...?

OpenStudy (anonymous):

OpenStudy (anonymous):

???

OpenStudy (mr.math):

Which problem do you need help with?

OpenStudy (anonymous):

all?

OpenStudy (anonymous):

Do you have any idea how to get started?

OpenStudy (mr.math):

I will help you with two problems, you'll need to try the other.

OpenStudy (anonymous):

okay

OpenStudy (anonymous):

btw show work?

OpenStudy (pokemon23):

Exchange medal time :)

OpenStudy (mr.math):

Lets start with the first one. We have two objects, one weighs 3 and the other weighs w. We need the sum of their weights to be 7. In mathematical notation \(3+w=7\). By subtracting \(3\) from both sides, we get \(w=7-3=4\).

OpenStudy (akshay_budhkar):

omg! blunder!

OpenStudy (mr.math):

For the second problem, there are 5 objects each weighs n and they add up to 25 mass unit. That's \(5n=25 \implies n=\frac{25}{5}\iff n=5\).

OpenStudy (mr.math):

Tell me how much does x weigh in problem 3.

OpenStudy (anonymous):

3? but i need help with showing work??

OpenStudy (mr.math):

Correct! You have \[x+x+7=`3\]

OpenStudy (mr.math):

x plus x is 2x. So \[2x+7=13\]

OpenStudy (mr.math):

Now, you need to isolate x from any number. So subtract 7 from both sides, \(2x+7-7=13-7\), which is the same as \[2x=6\]

OpenStudy (mr.math):

Now, you want to get rid of x's coefficient. Divide both sides by 2: \[x=3.\]

OpenStudy (mr.math):

Easy?!

OpenStudy (anonymous):

was that all for number 3?

OpenStudy (mr.math):

Hmm, yeah.

OpenStudy (anonymous):

can you help me on all of them il give u good answer?

OpenStudy (mr.math):

I would love to help you without even giving me good answer, but you won't learn anything this way. I want you to try, so you can learn from your mistakes.

OpenStudy (anonymous):

please only this assignment iv been trying all day

OpenStudy (anonymous):

???

OpenStudy (anonymous):

please??

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