Question

Convert the rectangular coordinates to polar coordinates with
r > 0 and 0 ≤ θ < 2π.

(-squareroot of 6, -squareroot of 2)

Answer 1

\[\theta = \arctan (-\sqrt{2}/-\sqrt{6}), r = \sqrt{6 + 2}\]

Answer 2

what is the radian for the \[\theta\]?

Answer 3

theta = .5234

Answer 4

is that \[\pi/2\] ?

Answer 5

π/2 = 1.57

Answer 6

im sorry for all the questions but I want to know what the theta you got but in radians