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cylindrical coordinates help!
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Sketch the solid whose volume is given by
\[\int\limits_{0}^{\pi/6}\int\limits_{0}^{\pi/2}\int\limits_{0}^{3} \rho ^{2} \sin \theta d \rho d \theta d \phi\]
what does this thing look like??
You mean spherical coordinates! lol!
yes, i do!
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Can you check if there was not a typo for sin phi instead of sin theta. The Jacobian for dV calls for a rho^2sin phi drho dtheta dphi.
If it is sin(phi), then it is a thirty-degree quarter open cone 3 units in radius opening towards the north pole, and situated in the first octant.
you're right, it was sin phi
how did you get the thirty degree part of that?
OH phi is measured from the top! I get you now.
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great, thanks!
You're welcome!
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