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9 ^–3x ≈ 7 ?
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solving\[9^{-3x}\approx7\]for x?
yess
first step is to get rid of the base 9 we do that by taking the log base 9 of both sides what do you have after that?
remember that\[\log_a{a^x}=x\]
yea thats true but i would go about it differently also shwenie check the answer of the one rixxar did for you
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okay thanks!
@turing test i actually like your way better, i was going to do it a diffent way but i agree with you your looking good
i was gonna take then to the LN but your way is way easier
thanks, taking the ln is just unnecessary
i agree ur way easier
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