solve x+>-3/11 write your solution using set builder notation. please show all work. the> is underlined
Hi! What is confusing you about this problem?
\[x \ge- {3\over11}\] Is this what the problem looks like: why is there a + after x?
thats how the problem is written
may be it's a mistake
you have to solve problem first than write it in set builder notation and the problem is x+2=-3/11
you can type ‘>=’ for the “greater than or equal to” sign (≥)
\[x+2 \ge -{3 \over 11}\] So, \[x \ge -{3 \over 11}-2\] \[x \ge -2{3 \over 11}\] or \[x \ge -{25 \over 11}\]
IF there is no other condition, like x is an integer, or x is a natural number: \[\left\{ x: x \in \mathbb{R}, \&\ x \ge -2{3\over11}\right\}\]
where did you get 25 from
\[2{3\over11} = {2\times 11\over 11} +{3\over11}={22\over 11} +{3\over11}={22+3\over11}={25\over11}\]
\[-2{3\over11} =-{25\over11}\] You could write the answer in set builder form just as : \[\left\{ x :x ≥-2 {3\over11} \right\} \]
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