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Suppose that ln 2=a and ln3=b. Use properties of logarithms to write each logarithm in terms of a and b ln0.5
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didn't you already post this like 3 questions down?
couldnt figure this one out
ktklown could you please help me after you are done here?
-a
please include all steps
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do you want to learn the material or just get an answer to copy?
a = ln2 0.5 = sin(a)^2 0.5 = -a
Can it be solved without trig? All of the other ones were solved without trig
a = ln 2 a^2 / ln 2^2 = e^a -a = 0.5
ehhh?
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\[\ln{0.5}=\ln{\frac{1}{2}}=\ln{\frac{3/3}{2}}=\ln 3 - \ln 3 - \ln 2\]
= b - b - a = -a
Finally a decent explanation
ktklown's methods are bizarre
yeah
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