Question

(9^2y)/3^(7-y) = (3^(4y+3))/27^(y-2) ???

y = ??? I've got 8/3.

Answer 1

the answer is y=4

Answer 2

how did you get that??

Answer 3

on the LHS

we have 3^4y/3^7-y

which i s 3^5y-7

on the rhs we have

3^4y+3/3^3y-6

which is 3^y+9


equating the powers on the 2 sides we get

y=4

Answer 4

like expoent will get 5y-7=y+9 from this you need calcule the y so 4y=16 so y=16/4 =4
y=4

Answer 5

like exponent wann to be - sorry

Answer 6

got it already?

Answer 7

understandably ?

Answer 8

tanvidais13 - ok ?

Answer 9

so 8/3 not is right

Answer 10

ahhhhhh, thank you SOOO much :) when i was making the base of 9 to 3, while doing the (3^2)^2y, i accidentally got 3^6y :P

Answer 11

ok good luck bye

Answer 12

thank youuu, and same you to as well :D

Answer 13

it took great deal of time

Answer 14

really?? It took me only a little time, but I DID get it wrong, so.... yeahh, i'm weird :P

Answer 15

haha and funny too