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Which of the following is the simplified form of ? (x^2-9)/(x-3)
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x+3
remember that:\[a^2-b^2=(a+b)(a-b)\]so:\[x^2-9=x^2-3^2=(x+3)(x-3)\]this can be used to cancel the (x-3) terms from numerator and denominator to get the answer @jimmyrep gave.
A,b,c or d x – 3, with the restriction x ≠ 3 x + 3, with the restriction x ≠ 3 x – 3, with the restriction x ≠ –3 x + 3, with the restriction x ≠ –3
remember we got the answer x+3 by dividing the numerator and denominator by (x-3). we cannot do this if x=3 as then we would be dividing by zero which is not a valid operation.
so what do you think the answer is?
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i said b
perfect! - well done.
thanks
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