Question

Add and simplify:

Answer 1

\[2x+8 \over x-4\] + \[x-7 \over x-4\]

Answer 2

add in the numerator, keep the denominator the same

Answer 3

When the denominators are the same you can close to ignore them for the addition process of the fractions and put them back later.

(2x+8) + (x-7)

We can gather like terms now.

(2x+8) + (x-7) = 3x+1

We must now add back the denominator we 'ignored' earlier.

\[\frac{3x+1}{x-4}\]

There isn't much you can simplify here, due to the fact that you have a plus sign in the between terms in both the denominator and the numerator.

Answer 4

\[2x+8+x-7=3x+1\]