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the wall is 1m thich and the out side diameter is 100m and the height is 5m what is the volume
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\[V=4/3 \pi r^2h\] First find the volume of the outside, then subtract the volume of the inside of the object to get the volume of the wall: Volume of outside: \[V=4/3\pi*(100/2)^2 * (5)\] V=52360 Volume of inside: \[V=4/3\pi*((100-2)/2)^2 * (5)\] you subtract the 2 from 100 because the walls are 1m thick, so that would be 2m off of the diameter V=50286 52360-50286=2074m^3 So final answer is V=2074m^3
the inside volume not the volume of the wall
I already told you the volume of the inside: it's 50286m^3
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