would 1 - 2cos^2(y) = 2sin^2(y) ?????
2 - 2cos^2(y) = 2sin^2(y)
learning trig for the first time?
^^
ITS NOT
Sorry. sin^2x + cos^2x = 1. So, 1-2cos^2x can't equal 2sin^2x.
nope, just got confused. Butt: wouldn't the example which I gave form the equation that: 2sin^2x + 2cos^2x = 1, therefore sin^2x + cos^2x = 1/2 ????
\( 1 - 2 \cos^2(y) = - \cos 2y \)
thats equal to 2
shinigami1m - sorry. I mis-read it first as 2 - 2cos^2x = 2sin^2x.
yeahhh, that's what I was confused about. So help me solve this: 2cs^2y - siny - 1 = 0.
cos or csc?
cos^2y = 1-sin^2y. Substitute. You get a quadratic equation in siny. Then solve.
sorry, cos, not cosec. ^Okayy, so lemme try that and see.
s^2 + c^2 = 1 2s^2 + 2c^2 = 2 is what im thinking
gotta use rads ;)
WHAT IS THIS :O
YOU FACE, SHAL'S. Finally rediscovered, after what: a million years??? :P
I think this method might work: 1 - 2 cos square y = 2 sin square y(Given) Or, 1 = 2 sin square y + 2 cos square y Or, 1 = 2(sin square y + cos square y) We get, 1 = 2 (Impossible!!!!)
Sometimes the question may be wrong.
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