Question

how to do I change lny = -1/2lnx + 6.8 into the form

y = Ax^b ???

Answer 1

stick an e on it

Answer 2

some use of ( ) to clean up the equation might be useful ...

Answer 3

ummm...... can you expand on that???? lets say I have this:

lny = lnx^-1/2 + 6.8

Now what??

Answer 4

lny=lnx^(-0.5)+6.8
y=x^-0.5*e^6.8

Let e^6.8 be A

y=Ax^-0.5

Answer 5

bases and logs are inverses, they cancel each other out

Answer 6

lny = lnx^-1/2 + 6.8

e^(lny = lnx^-1/2 + 6.8 )

y = x^-1/2 * e^(6.8)

Answer 7

ohhhhhhh, zed, that makes sense.

Answer 8

and you too, amistre64 :D

Answer 9

\begin{array}l\color{red}{\text{y}}\color{orange}{\text{a}}\color{#9c9a2e}{\text{y}}\color{green}{\text{!}}\color{blue}{\text{!}}\color{purple}{\text{ }}\color{purple}{\text{:}}\color{red}{\text{)}}\color{orange}{\text{}}\end{array}

Answer 10

^lol