We toss a dice 1,000 times. How many times do we expect to have the sum of the two dice equal to 4? A. about 250 B. about 167 C. about 83 D. about 42
Well, i would say C
We toss two dice 1000 times?
wait man, the question is tripping me up
Wait a second. What's the set up? Is it: - We roll TWO dice 1000 times and we're looking at the sum of their numbers or - We roll ONE die 1000 times and we add up the numbers for every pair of rolls?
can i get a clarification please, is it two or 1
two dice i guess
Well, it has to be two
It says we TOSS so I guess aka ROLL TWO die..
Ok. So if you roll two dice, there 6 x 6 = 36 outcomes. How many of those add up to 4?
there are 36 outcomes and 3 of those add to 4
shh! You've giving it away :-)
there are 6*6 possible combinations for tossing two dice once
now, she still has to find the probalblilty
Ya I don't know soooo...
the question now is: what proportion or fraction of the rolls sum to 4?
Think of this, considering the information that we have given you, what is the probablility of a sum of 4 on one roll?
Suppose that number is p. Then the number of rolls that we expect to add up to 4 will be p times the number of rolls, i.e., 1000p. So what's p? What proportion or fraction of the 36 gives us the result we want?
83?
yehh 83 cox 1000/12 is approx equal to 83
So thats right then?
the exact answer is 250/3, or 83.3 (repeating)
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