Question

Solve for h
q=2h-2u
The solution is h=

Answer 1

add 2u to both sides, then divide both sides by 2

Answer 2

Solve for H q=2h-2u what is the solution

Answer 3

please clarify and write the solution for me

Answer 4

I'm afraid I'm going to make you try to think about it, not just give away the answer.

Take your original expression
q=2h-2u
and add 2u to BOTH SIDES
what do you have now?

Answer 5

q=2h+2u-2u+2u so what is the solution for H I didnt do this right did I

Answer 6

no, you added 2u twice, and just to just the right side.
I asked you to just ADD 2u (only once please) to BOTH sides:

q+2u=2h-2u+2u

can you simplify what is above (hint: what is -2u+2u )?

Answer 7

0

Answer 8

yes\[-2u+2u=0\]so using that, what is\[q+2u=2h-2u+2u\]after simplification?

Answer 9

2

Answer 10

no that is quite wrong unfortunately :(
can you show me some work so I can see where you made your mistake? I don't see how you got a 2 from anywhere...

Answer 11

this is so confusing for me I am doing terrible in this course, I still dont know why we need this to become a PO

Answer 12

q-(2u0(2)

Answer 13

I don't know what a PO is (unless you mean police officer or public official), but you have clearly been neglecting your math work for some time now. Watch this:
q=2h-2u
+2u +2u
------------
q+2u=2h

Above is how teachers usually show it on the blackboard.

remembering that
\[-2u+2u=0\]do you see how that is the same as
\[q=2h-2u\]add 2u to both sides:
\[q+2u=2h-(2u+2u)=2h+0=2h\]?
use whatever way makes the most sense to you.

Answer 14

now it make ssense too me so the solution is 2h ty so much for all ur teachings (probation officer)

Answer 15

NO!
we are not done, and 2h is not the answer.
we were asked to solve for h!
that means we need h to be by itself...

Answer 16

ok

Answer 17

so far we have\[2h=q+2u\]divide both sides by 2 to isolate h.
try it and tell me what you get...

Answer 18

1

Answer 19

I'm sorry, but you need to go back to the basics. I don;t think anything I can say will help you, so this one time I will give you the answer...\[\frac{2h}{2}=\frac{q+2u}{2}\to h=\frac{q}{2}+u\]please try to study this and see what you are missing in your understanding.

Answer 20

ty