Question

Evaluate the function at each specified value of the independent variable and simplify. (If an answer is undefined, enter UNDEFINED.)
h(t) = t2 − 2t

Answer 1

specify some values...

Answer 2

for example if we have t=0,
we have
wherever there is a t, we plug in zero
\[h(0)=0^2-2(0)=0-0=0\]
another example if we have t=1,
we have
wherever there is a t, we plug in one
\[h(1)=1^2-2(1)=1-2=-1\]
last example if we have t=-3
we have
wherever there is a t, we plug in negative three
\[h(-3)=(-3)^2-2(-3)=9-(-6)=9+6=15\]
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Do you think polynomials are undefined anywhere?