Question

solve each system of equations:
2) x+y+z=0
2x+3y+2z= -1
x-y+z= 2

Answer 1

- assume first with 3rd

x+y+z=0
x-y+z=2
---------
2x+2z=2 so x+y=1 so x=1-y

- multiply first by -2 and assume with second

-2x-2y-2z=0
2x+3y+2z=-1
---------------
0 y 0 = -1

so y=-1 than x=1-(-1)=1+1=2 so x=2
- than x+y+z=0 so 2-1+z=0 so 1+z=0 so z=-1

x=2
y=-1
z=-1