if a third term of an arithmetic is 14 and the 8th term is -1, find the values of a1 and d of the sequence
How many steps from the 3rd term and the 8th term?
d=-5/2
a1 is 19
how do you do it
Just write the series dude a1, a1+d, a1+2d(3rd term=14) , a1+3d, ........a1+7d(8th term=-1) Solve two equations for a1 and d a1+2d=14 a1+7d=-1 Is it ok?????
I will try
Got it dude????????
not yet they do not want me to list them
Didnt got u
U have been given with the 3rd and 8th terms to find first term and arith.difference of the series right????? Then use the formula u have for nth term a+(n-1)d then substitute n value for ur terms given and eqaute to their vale Solve the equations and get the result This will the same thing i have done above
oh ok
sorry but I do not have a1 and d. and whats n
n is term given to u for the third term it is 3 and 8th term it is 8 and the expression in each equals to the value given to you
is it third=14 and 8th=-1
yeah exactly a+(3-1)d=14 a+(8-1)d=-1
thats the method of two equation then sub 2 into 1 am I right
yeah i think you know to solve two simultaneous equations right????
yes I just did not get it at the first. I will let you know how I went
It appears like the delta between terms is -3. Assuming a1 is the first term of the series, it has to be 14+3+3 = 20.
I think I did it d=3 and a1=8
Atchyut are you there?
how does this work I did the second time and got d=5/3=1.6 and a1=10.8. both work so which one to use. help please
ok wait i will tell
you have the two equations a1+2d=14 a1+7d=-1 right????
yes did and the results are the ones written above
Subtract the second equation from first then a1 and a1 gets cancelled we will remain with 2d-7d=14-(-1) -5d=15 and d= -15/5 =-3 and now substitute d=-3 in first equation a1-6=14 gives a1=20. So a1 is 20 and d=-3 At first I thought something wrong and kept pth term equation inplace of 8 th term and so we get it like that
ok I will do it again
ok
how did you get -3 instead of 3
Once check my solution dude
think once first term is greater than the next terms.. how this is possible????? It is possible only when the common difference is negative dude got it????
its geting more confusing because I did and got d=3 and a1=8 and tryed to do the sequence and it works but does not work for 8th term=-1
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