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Mathematics 13 Online
OpenStudy (anonymous):

At a high school cafeteria, diners can choose one vegetable from a choice of 2 vegetables, one meat from a choice of 3 meats, one serving of bread from among 2 breads, and a dessert from among 3 desserts. How many meal configurations are possible?

OpenStudy (dumbcow):

Trick is to just multiply all the possible choices: 2*3*2*3

OpenStudy (mertsj):

2X3X2X3

OpenStudy (anonymous):

36! Thank you guys :)

OpenStudy (anonymous):

It's is not 36! but only 36. They are widely different in combinatorics.

OpenStudy (anonymous):

36!, some cafeteria!!

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