Question

solve the inequality x^2+x-6>or equal to-4 by using a table and a graph

Answer 1

\[x^2+x-6\ge -4 \implies x^2+x-2\ge0 \implies (x+2)(x-1)\ge0 \]

Answer 2

\( \Rightarrow x \le -2 \text{ or } x \gt 1 \)

Answer 3

Now, you need to study the intervals as shown below:

-2 1
---------------------------------
- + + x+2
- - + x-1
+ - + (x+2)(x-1)

Answer 4

So our intervals are then \((-\infty,-2] + [1,\infty) \).

Answer 5

Just a minute typo: \[ \Rightarrow x \le -2 \text{ or } x \ge 1 \]

Answer 6

Yeah.

Answer 7

Thanks!

Answer 8

What's the latex for union? @FFM

Answer 9

\( \cup \cap \)

Answer 10

lol

Answer 11

;)