solve the inequality x^2+x-6or equal to-4 by using a table and a graph

Question

solve the inequality x^2+x-6>or equal to-4 by using a table and a graph

mr.math · Answer

$$x^2+x-6\ge -4 \implies x^2+x-2\ge0 \implies (x+2)(x-1)\ge0 $$

anonymous · Answer

$ \Rightarrow x \le -2 \text{ or } x \gt 1 $

mr.math · Answer

Now, you need to study the intervals as shown below:

               -2                     1
---------------------------------
      -                   +                    +               x+2
      -                    -                      +              x-1
       +                    -                     +            (x+2)(x-1)

mr.math · Answer

So our intervals are then $(-\infty,-2] + [1,\infty) $.

anonymous · Answer

Just a minute typo: $$ \Rightarrow x \le -2 \text{ or } x \ge 1 $$

mr.math · Answer

Yeah.

anonymous · Answer

Thanks!

mr.math · Answer

What's the latex for union? @FFM

anonymous · Answer

$ \cup \cap $

mr.math · Answer

lol

anonymous · Answer

;)