Mathematics
12 Online
OpenStudy (anonymous):
What is the value of h in the function f(x)=1/2(x=5)2-9?
A. 5
B. 1/2
C. 9
D. -5
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OpenStudy (across):
I am very confused: Why do you have a second equals sign in the middle of the function, and where is h?
OpenStudy (anonymous):
they didnt give me an h value :-/
and that was supposed to be x=5
OpenStudy (across):
I am now more confused. n_n
myininaya (myininaya):
what? I'm confused too. The way you typed your problem is that exactly the way it looks?
OpenStudy (anonymous):
yeah. but the 2 is small and its raised
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myininaya (myininaya):
and inside the parenthesis is x=5?
myininaya (myininaya):
\[f(x)=\frac{1}{2}(x \pm 5)^2-9\]
i think it should either be + or -
OpenStudy (across):
\[f(x)=\frac{1}{2}(x=5)^2-9...\]I can't seem to make any sense of this.
myininaya (myininaya):
and I'm assuming you want to find the x coordinate of the parabola
OpenStudy (anonymous):
Ummm, I guess.. I dont know. Im really really bad at math
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myininaya (myininaya):
can you write the function down one more time?
myininaya (myininaya):
and i meant x coordinate of the vertex of the parabola lol
OpenStudy (anonymous):
f(x)=1/2(x+5)2-9
myininaya (myininaya):
ok great!
myininaya (myininaya):
now it makes more sense
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OpenStudy (anonymous):
oh. sorry! haha
myininaya (myininaya):
\[f(x)=\frac{1}{2}(x+5)^2-9\]
\[f(x)=a(x-h)^2+k\]
what is h?
myininaya (myininaya):
well we want -h=5 right?
myininaya (myininaya):
so if -h=5, then h=?
OpenStudy (anonymous):
-5? lol sorry, im super weak in math
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myininaya (myininaya):
-5 is tight!
myininaya (myininaya):
i mean right*
OpenStudy (anonymous):
YAY!! :D
OpenStudy (anonymous):
can you help me with more? Ive got a ton
myininaya (myininaya):
Ok
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myininaya (myininaya):
But you have to give me a sprite or dr. pepper
OpenStudy (anonymous):
I'll give you both!
myininaya (myininaya):
lol
myininaya (myininaya):
ok thanks for the imaginary soda