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What is the limit when x approaches 0, (1/x)-(1/x^2+x)? answer key says: 1 using a graph calculator i see its negative infinity anythoughts or steps to use?
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\[\lim_{x \rightarrow 0}{1 \over x}-{1 \over x^2+x}\]???
yes that is the setup, sorry if i formatted incorrectly
Can you combine the fractions? once you've done that L'hospital's rule takes care of it.
The limit is 1 by the way, not sure what you put in you calculator, but if you wrote it as above it is the wrong syntax.
Thank you, now it makes sense.
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good, congratulations and happy new year :)
HAPPY NEW YEAR!!!! haha
happy new years eve and u should give him a medal
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