Question

Given the linear equation y= 1/3x-3 find the y-coordinates of the points (-6,_)(-3,_)and (6,_)

Answer 1

just put the numbers u're given and u'll find the one which is missing, for example
y=x/3-3 x=-6
y=-6/3-3=-3-3=-6

Answer 2

?

Answer 3

(x,y) is a coordinate point

Answer 4

you are given the x find the y

Answer 5

i know but how

Answer 6

\[y=\frac{1}{3}x-3\]
(-6,_) x = -6
\[y=\frac{1}{3}(-6)-3\]

Answer 7

know how to multiply fractions?

Answer 8

its been a few years an im not that good at algebra

Answer 9

k, a whole number can be written as a fraction over 1
\[\frac{1}{3}(-6)=\frac{1}{3}*\frac{-6}{1}=\frac{-6}{3}\]

Answer 10

ok

Answer 11

Does that help any?

Answer 12

yes but do i need to draw up a grapgh i dont know how to find the y coordinate just multiply fractions for ex.-6/1

Answer 13

The y coordinate is given by the equation
\[y=\frac{1}{3}x-3\]

Answer 14

replace the x with the value given in the coordinates (-6,_)
\[y=\frac{1}{3}(-6)-3\]
solve that and you have the y value of that coordinate

Answer 15

how

Answer 16

plz help me someone

Answer 17

-5

Answer 18

is that right

Answer 19

! yes

Answer 20

(-6,-5) is your first coordinate

Answer 21

thank u but can you set the other 2 up for me then ill wk them

Answer 22

(-3, )
\[y=\frac{1}{3}(-3)-3\]
(6, )
\[y=\frac{1}{3}(6)-3\]

Answer 23

ok (-3,-4)

Answer 24

and (6,-1)

Answer 25

good job

Answer 26

thank you so much,,im super grateful

Answer 27

glad to try and help =)

Answer 28

udid :)

Answer 29

good work guys