Question

what is distance between (3,-2)and (-3,-6) on a graph?

Answer 1

\[d=\sqrt{[\delta(x)]^2+[\delta(y)]^2}\]

Answer 2

\[distance = \sqrt{(x2 - x1)^{2}+(y2-y1)^{2}}\]
\[d=\sqrt{(-6)^{2}+(-4)^{2}} = \sqrt{36+16}=\sqrt{52} = 2\sqrt{13}\]

Answer 3

thanks

Answer 4

welcome :D

Answer 5

:D

Answer 6

can it be written as a vector?

Answer 7

yep

Answer 8

@ lollylau the vector is (-6,-4)