graph the following quadratic equation:
y+12+x^2=4x^2-7x
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OpenStudy (mertsj):
y=3x^2-7x-12
OpenStudy (anonymous):
ok i have that but i dont know how to graph it
'
OpenStudy (mertsj):
x=-b/2a=7/6. So the x coordinate of the vertex is 7/6. Now plug 7/6 in to find the y coordinate of the vertex
OpenStudy (mertsj):
So the vertex is (7/6,-14 11/12)
OpenStudy (mertsj):
Vertex is (7/6,-16 1/12)
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OpenStudy (mertsj):
Now choose an x value to the right of 7/6 like 2 and plug it in to find y.
OpenStudy (mertsj):
You will get (2,-14)
OpenStudy (mertsj):
Use symmetry to get the corresponding point to the left of the vertex.
OpenStudy (mertsj):
Now choose another x value perhaps 3 and plug it in. You will get -6. So graph (3,-6). Graph the corresponding point to the left of the vertex. That should be enough to draw the curve.
OpenStudy (anonymous):
i am so lost'
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OpenStudy (anonymous):
Two versions of the plotted quadratic expression is attached.
OpenStudy (anonymous):
ok thank you
OpenStudy (mertsj):
So money, do you still need help?
OpenStudy (mertsj):
I see you said you are so lost.
OpenStudy (anonymous):
no i got it
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